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(A) pack of cards contains $52$ cards in total.The number of aces in a pack is $4$.The probability of drawing an ace in a single draw is $P(A) = \frac

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$\frac{1}{169}$

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(A) pack of cards contains $52$ cards in total.The number of aces in a pack is $4$.The probability of drawing an ace in a single draw is $P(A) = \frac{4}{52} = \frac{1}{13}$.Since the cards are drawn with replacement,the probability of drawing an ace in the second draw remains the same,$P(A) = \frac{1}{13}$.The probability of drawing two aces successively is $P(A \cap A) = P(A) 	imes P(A) = \frac{1}{13} 	imes \frac{1}{13} = \frac{1}{169}$.

Two cards are drawn successively with replacement from a pack of $52$ cards. The probability of drawing two aces is

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