Two cards are drawn successively with replace | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Total number of cards $= 52$. Total number of queens $= 4$. Probability of getting a queen in one draw,$p = \frac{4}{52} = \frac{1}{13}$. Probabil

Vedclass · Accepted Answer

$\frac{2}{13}$

Vedclass · Answer

(C) Total number of cards $= 52$. Total number of queens $= 4$. Probability of getting a queen in one draw,$p = \frac{4}{52} = \frac{1}{13}$. Probability of not getting a queen,$q = 1 - p = \frac{12}{13}$. Since the cards are drawn with replacement,this follows a binomial distribution $B(n, p)$ with $n = 2$ and $p = \frac{1}{13}$. The mean of a binomial distribution is given by $E(X) = np$. $E(X) = 2 	imes \frac{1}{13} = \frac{2}{13}$.

Two cards are drawn successively with replacement from a well-shuffled pack of $52$ cards. The mean of the number of queens is:

Similar Questions

The probability of success $p$ for the Binomial distribution satisfying the relation $4 P(X=4) = P(X=2)$ with parameter $n=6$ is

$A$ pair of fair dice is thrown $4$ times. If getting the same number on both dice is considered as a success,then the probability of exactly two successes is:

Two cards are drawn successively with replacement from a well-shuffled deck of $52$ cards. The mean of the number of aces is:

If a fair coin is tossed $10$ times,find the probability of exactly six heads.

If $X \sim B\left(8, \frac{1}{2}\right)$,then $P(|X-4| \leq 2)=$

Vedclass Test Series

Exam Paper Generator

Online Exam Module