Two charges,each equal to eta q (where eta^{- | vedclass

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(C) Let the two charges be $q_1 = q_2 = \eta q$ at two vertices of an equilateral triangle of side $a$. The electric field at the third vertex due to

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$E_3 > E_0$

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(C) Let the two charges be $q_1 = q_2 = \eta q$ at two vertices of an equilateral triangle of side $a$. The electric field at the third vertex due to each charge is $E_1 = E_2 = \frac{\eta q}{4\pi\varepsilon_0 a^2}$.Since the angle between the two electric field vectors is $60^\circ$,the resultant electric field $E_3$ is given by:$E_3 = \sqrt{E_1^2 + E_2^2 + 2E_1 E_2 \cos 60^\circ} = \sqrt{E_1^2 + E_1^2 + 2E_1^2(1/2)} = \sqrt{3} E_1$.Substituting $E_1 = \eta E_0$,we get $E_3 = \sqrt{3} \eta E_0$.Given that $\eta^{-1}  1$.Therefore,$E_3 = (\sqrt{3} \eta) E_0 > 1 \cdot E_0$,so $E_3 > E_0$.

Two charges,each equal to $\eta q$ (where $\eta^{-1} < \sqrt{3}$),are placed at two corners of an equilateral triangle of side $a$. The electric field at the third corner is $E_3$. If $E_0 = \frac{q}{4\pi\varepsilon_0 a^2}$,then which of the following is correct?

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