(C) Charge flows from higher potential to lower potential. The potential of a capacitor is given by $V = \frac{Q}{C}$.For circuit $(a)$:Potential of l

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Charges flow from $R$ to $L$ in $(a)$ and from $L$ to $R$ in $(b)$

(C) Charge flows from higher potential to lower potential. The potential of a capacitor is given by $V = \frac{Q}{C}$.For circuit $(a)$:Potential of left capacitor $V_L = \frac{2Q}{3C} = \frac{2}{3} \frac{Q}{C}$.Potential of right capacitor $V_R = \frac{Q}{C}$.Since $V_R > V_L$, charge flows from $R$ to $L$.For circuit $(b)$:Potential of left capacitor $V_L = \frac{2Q}{2C} = \frac{Q}{C}$.Potential of right capacitor $V_R = \frac{Q}{2C} = 0.5 \frac{Q}{C}$.Since $V_L > V_R$, charge flows from $L$ to $R$.

Class 12 Physics Electrostatic Potential and Capacitance Sharing of Charge in Capacitor Circuit

Medium

Two circuits $(a)$ and $(b)$ have charged capacitors with capacitances and charges as shown in the figures. The switches are initially open. On closing the switches, what happens to the charge flow?

AIEEE 2012 All AIEEE

A
No charge flows in $(a)$ but charge flows from $R$ to $L$ in $(b)$
B
Charges flow from $L$ to $R$ in both $(a)$ and $(b)$
C
Charges flow from $R$ to $L$ in $(a)$ and from $L$ to $R$ in $(b)$
D
No charge flows in $(a)$ but charge flows from $L$ to $R$ in $(b)$

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Electrostatic Potential and Capacitance

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Sharing of Charge in Capacitor Circuit

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Two circuits $(a)$ and $(b)$ have charged capacitors with capacitances and charges as shown in the figures. The switches are initially open. On closing the switches, what happens to the charge flow?

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