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(D) The maximum intensity for the superposition of two coherent waves is given by:$I_{\max} = (\sqrt{I_1} + \sqrt{I_2})^2$Given $I_1 = I$ and $I_2 = 4

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$9I$ and $I$

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(D) The maximum intensity for the superposition of two coherent waves is given by:$I_{\max} = (\sqrt{I_1} + \sqrt{I_2})^2$Given $I_1 = I$ and $I_2 = 4I$:$I_{\max} = (\sqrt{I} + \sqrt{4I})^2 = (\sqrt{I} + 2\sqrt{I})^2 = (3\sqrt{I})^2 = 9I$The minimum intensity for the superposition of two coherent waves is given by:$I_{\min} = (\sqrt{I_1} - \sqrt{I_2})^2$$I_{\min} = (\sqrt{I} - \sqrt{4I})^2 = (\sqrt{I} - 2\sqrt{I})^2 = (-\sqrt{I})^2 = I$Thus, the maximum and minimum intensities are $9I$ and $I$ respectively.

Two coherent monochromatic beams of intensities $I$ and $4I$ respectively are superposed. The maximum and minimum intensities in the resulting pattern are

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