(B) For a dark fringe (minima) in Young's double slit experiment,the path difference $\Delta x$ is given by the formula: $\Delta x = (n - \frac{1}{2})

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(B) For a dark fringe (minima) in Young's double slit experiment,the path difference $\Delta x$ is given by the formula: $\Delta x = (n - \frac{1}{2}) \lambda$,where $n$ is the order of the dark fringe and $\lambda$ is the wavelength of light.For the second order dark fringe,$n = 2$.Substituting the values: $\Delta x = (2 - \frac{1}{2}) \times 5000 \text{ Å} = \frac{3}{2} \times 5000 \text{ Å} = 7500 \text{ Å}$.Converting to micrometers: $7500 \text{ Å} = 7500 \times 10^{-10} \text{ m} = 0.75 \times 10^{-6} \text{ m} = 0.75 \mu m$.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

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Two coherent sources $O_1$ and $O_2$ in Young's double slit experiment are illuminated with monochromatic light of wavelength $5000 \text{ Å}$. If a second order dark fringe is formed at a point $R$ on the screen,the path difference $O_1 R \sim O_2 R$ is (in $\mu m$)

AP EAMCET 2022 All AP EAMCET

A
$7.5$
B
$0.75$
C
$0.075$
D
$75$

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Young's Double Slit Experiment (YDSE)

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In Young's double slit experiment,white light is used. The separation between the slits is $b$. The screen is at a distance $d$ $(d >> b)$ from the slits. Some wavelengths are missing exactly in front of one slit. These wavelengths are

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Two identical narrow slits $S_1$ and $S_2$ are illuminated by light of wavelength $\lambda$ from a point source $P$. If,as shown in the diagram,the light is then allowed to fall on a screen,and if $n$ is a positive integer,the condition for destructive interference at $Q$ is that

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In Young’s double slit experiment,a minimum is obtained when the phase difference of superimposing waves is:

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Two slits are $1 \, mm$ apart from each other and the distance of the screen is $1 \, m$. If illuminated with light of wavelength $5 \times 10^{-7} \, m$,the distance between the $3^{rd}$ dark fringe and the $5^{th}$ bright fringe is......$mm$.

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If fringe width is $0.4 \,mm$, the distance between the fifth bright and third dark band on the same side is: (in $\,mm$)

MediumMHT CET 2009

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Two coherent sources $O_1$ and $O_2$ in Young's double slit experiment are illuminated with monochromatic light of wavelength $5000 \text{ Å}$. If a second order dark fringe is formed at a point $R$ on the screen,the path difference $O_1 R \sim O_2 R$ is (in $\mu m$)

Similar Questions

In Young's double slit experiment,white light is used. The separation between the slits is $b$. The screen is at a distance $d$ $(d >> b)$ from the slits. Some wavelengths are missing exactly in front of one slit. These wavelengths are

Two identical narrow slits $S_1$ and $S_2$ are illuminated by light of wavelength $\lambda$ from a point source $P$. If,as shown in the diagram,the light is then allowed to fall on a screen,and if $n$ is a positive integer,the condition for destructive interference at $Q$ is that

In Young’s double slit experiment,a minimum is obtained when the phase difference of superimposing waves is:

Two slits are $1 \, mm$ apart from each other and the distance of the screen is $1 \, m$. If illuminated with light of wavelength $5 \times 10^{-7} \, m$,the distance between the $3^{rd}$ dark fringe and the $5^{th}$ bright fringe is......$mm$.

If fringe width is $0.4 \,mm$, the distance between the fifth bright and third dark band on the same side is: (in $\,mm$)

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