Two coherent sources have an intensity ratio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the ratio of intensities of two coherent sources is $\frac{I_1}{I_2} = \frac{100}{1}$.Let the amplitudes be $a_1$ and $a_2$. Since $I \propt

Vedclass · Accepted Answer

$121 : 81$

Vedclass · Answer

(B) Given the ratio of intensities of two coherent sources is $\frac{I_1}{I_2} = \frac{100}{1}$.Let the amplitudes be $a_1$ and $a_2$. Since $I \propto a^2$,we have $\frac{a_1}{a_2} = \sqrt{\frac{I_1}{I_2}} = \sqrt{\frac{100}{1}} = \frac{10}{1}$.The ratio of maximum to minimum intensity is given by the formula:$\frac{I_{\max}}{I_{\min}} = \left( \frac{a_1 + a_2}{a_1 - a_2} \right)^2$.Substituting the values,we get:$\frac{I_{\max}}{I_{\min}} = \left( \frac{10 + 1}{10 - 1} \right)^2 = \left( \frac{11}{9} \right)^2 = \frac{121}{81}$.Thus,the ratio is $121 : 81$.

Two coherent sources have an intensity ratio of $100 : 1$ and are used to obtain the phenomenon of interference. What is the ratio of the maximum to the minimum intensity?

Similar Questions

Two light waves with amplitudes in the ratio $3 : 1$ produce interference. The ratio of the maximum to minimum intensity is

In an interference experiment, the path difference between two interfering waves at a point $A$ on the screen is $\lambda/3$, where $\lambda$ is the wavelength of these waves, and at another point $B$ the path difference is $\lambda/6$. The ratio of intensities at points $A$ and $B$ is . . . . . . .

In the phenomenon of interference:

Explain the intensity at the point of superposition of waves emanating from coherent and incoherent sources.

Two coherent sources whose intensity ratio is $64: 1$ produce interference fringes. The ratio of intensities of maxima and minima is

Vedclass Test Series

Exam Paper Generator

Online Exam Module