Two coherent sources of intensities,I_1 and I | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The resultant intensity $I_R$ of two coherent sources is given by the formula: $I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$,where $\phi$ is the p

Vedclass · Accepted Answer

$(\sqrt{I_1} + \sqrt{I_2})^2$

Vedclass · Answer

(D) The resultant intensity $I_R$ of two coherent sources is given by the formula: $I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$,where $\phi$ is the phase difference between the two waves.For maximum intensity,the phase difference $\phi$ must be an even multiple of $\pi$,i.e.,$\phi = 0, 2\pi, 4\pi, \dots$,which makes $\cos \phi = 1$.Substituting $\cos \phi = 1$ into the formula,we get: $I_{max} = I_1 + I_2 + 2\sqrt{I_1 I_2}$.This expression can be written as a perfect square: $I_{max} = (\sqrt{I_1} + \sqrt{I_2})^2$.

Two coherent sources of intensities,$I_1$ and $I_2$ produce an interference pattern. The maximum intensity in the interference pattern will be

Similar Questions

The resultant amplitude in interference with two coherent sources depends upon:

For constructive interference to take place between two monochromatic light waves of wavelength $\lambda$, the path difference should be

For obtaining maximum contrast between the bright and dark fringes in an interference pattern, the intensities of the two light coherent sources should be

When a light wave undergoes reflection at the interface from air to glass,the change in phase of the reflected wave is equal to

Two light waves of intensities $I_0$ and $9I_0$ superpose at a point to produce a resultant intensity of $7I_0$. Calculate the phase difference between the light waves.

Vedclass Test Series

Exam Paper Generator

Online Exam Module