Two coherent sources of intensity ratio $1 : 4$ produce an interference pattern. The fringe visibility will be

Two coherent sources of intensities $I_1$ and $I_2$ produce an interference pattern on a screen. The maximum intensity $I_{max}$ in this interference pattern is:

Four light sources produce the following four waves:
$(i)$ $y_1 = a \sin(\omega t + \phi_1)$
(ii) $y_2 = a \sin(2\omega t)$
(iii) $y_3 = d' \sin(\omega t + \phi_2)$
(iv) $y_4 = d' \sin(3\omega t + \phi)$
Superposition of which two waves gives rise to interference?

Two waves coming from two coherent sources,having different intensities,interfere. The ratio of their maximum intensity to the minimum intensity is $25$. What is the ratio of the intensities of the sources?

Two coherent waves of intensities $I_1$ and $I_2$ produce an interference pattern. The maximum intensity of the interference pattern is .....

The ratio of the amplitudes of two interfering waves is $3 : 4$. What is the ratio of their intensities?