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(A) The induced e.m.f. in coil $P$ due to the changing current in coil $Q$ is given by $\varepsilon_P = M \frac{dI_Q}{dt}$,where $M$ is the mutual ind

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$2.7$

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(A) The induced e.m.f. in coil $P$ due to the changing current in coil $Q$ is given by $\varepsilon_P = M \frac{dI_Q}{dt}$,where $M$ is the mutual inductance.Given $\varepsilon_P = 15 \ mV = 15 	imes 10^{-3} \ V$ and $\frac{dI_Q}{dt} = 10 \ A/s$.$15 	imes 10^{-3} = M 	imes 10 \implies M = 1.5 	imes 10^{-3} \ H = 1.5 \ mH$.The magnetic flux $\phi_Q$ linked with coil $Q$ when current $I_P$ flows through coil $P$ is given by $\phi_Q = M I_P$.Given $I_P = 1.8 \ A$ and $M = 1.5 \ mH$.$\phi_Q = 1.5 \ mH 	imes 1.8 \ A = 2.7 \ mWb$.

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