Two compounds with molecular formula $C_4H_6$ are available. If one of the compounds can react with soda amide $(NaNH_2)$ while the second cannot react with it,identify these two organic compounds.
- A$But-1-yne$ and $But-2-yne$
- B$But-1-ene$ and $But-2-ene$
- C$Butane$ and $Isobutane$
- D$1,3-Butadiene$ and $1,2-Butadiene$
Explore More
Similar Questions
The hydrocarbon which can react with sodium in liquid ammonia is
MediumAIEEE 2008
View SolutionThe catalyst required for the dimerization of acetylene to form chloroprene is ....
Medium
View Solution$CaC_2 + 2D_2O \longrightarrow$ "$P$" $+ Ca(OD)_2$
In the above reaction,the product "$P$" is:
In the above reaction,the product "$P$" is:
The simplest alkyne is represented by which of the following?
Easy
View SolutionIdentify the structure of the final product $(D)$ in the following sequence of reactions:
$Ph-CO-CH_3$ $\xrightarrow{PCl_5, \Delta} A$ $\xrightarrow{3 \text{ eq. } NaNH_2/NH_3} B$ $\xrightarrow{\text{Acidify}} C$ $\xrightarrow{1. B_2H_6, 2. H_2O_2/OH^-} D$
Total number of $sp^2$ hybridised carbon atoms in product $D$ is:
$Ph-CO-CH_3$ $\xrightarrow{PCl_5, \Delta} A$ $\xrightarrow{3 \text{ eq. } NaNH_2/NH_3} B$ $\xrightarrow{\text{Acidify}} C$ $\xrightarrow{1. B_2H_6, 2. H_2O_2/OH^-} D$
Total number of $sp^2$ hybridised carbon atoms in product $D$ is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo