Two concentric circular coils X and Y of radi | vedclass

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(C) Radius of coil $X$,$r_{1} = 16\; cm = 0.16\; m$.Radius of coil $Y$,$r_{2} = 10\; cm = 0.1\; m$.Number of turns in coil $X$,$n_{1} = 20$.Number of

Vedclass · Accepted Answer

$1.57 	imes 10^{-3}\; T$ (towards West)

Vedclass · Answer

(C) Radius of coil $X$,$r_{1} = 16\; cm = 0.16\; m$.Radius of coil $Y$,$r_{2} = 10\; cm = 0.1\; m$.Number of turns in coil $X$,$n_{1} = 20$.Number of turns in coil $Y$,$n_{2} = 25$.Current in coil $X$,$I_{1} = 16\; A$.Current in coil $Y$,$I_{2} = 18\; A$.The magnetic field at the centre of a circular coil is $B = \frac{\mu_{0} n I}{2 r}$.For coil $X$,$B_{1} = \frac{4\pi 	imes 10^{-7} 	imes 20 	imes 16}{2 	imes 0.16} = 4\pi 	imes 10^{-4}\; T$ (towards East).For coil $Y$,$B_{2} = \frac{4\pi 	imes 10^{-7} 	imes 25 	imes 18}{2 	imes 0.10} = 9\pi 	imes 10^{-4}\; T$ (towards West).Since the fields are in opposite directions,the net magnetic field is $B = B_{2} - B_{1} = (9\pi - 4\pi) 	imes 10^{-4} = 5\pi 	imes 10^{-4}\; T$.$B \approx 1.57 	imes 10^{-3}\; T$ (towards West).

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