Two concentric coils each of radius equal to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetic field at the center of a circular coil is given by $B = \frac{\mu_0 i}{2r}$.Since the two coils are placed at right angles,their magn

Vedclass · Accepted Answer

$5 	imes 10^{-5}$

Vedclass · Answer

(A) The magnetic field at the center of a circular coil is given by $B = \frac{\mu_0 i}{2r}$.Since the two coils are placed at right angles,their magnetic fields $B_1$ and $B_2$ will also be perpendicular to each other.The resultant magnetic field is $B_{net} = \sqrt{B_1^2 + B_2^2}$.Substituting $B_1 = \frac{\mu_0 i_1}{2r}$ and $B_2 = \frac{\mu_0 i_2}{2r}$,we get $B_{net} = \frac{\mu_0}{2r} \sqrt{i_1^2 + i_2^2}$.Given $r = 2\pi \, cm = 2\pi 	imes 10^{-2} \, m$,$i_1 = 3 \, A$,$i_2 = 4 \, A$,and $\mu_0 = 4\pi 	imes 10^{-7} \, Wb/A \cdot m$.$B_{net} = \frac{4\pi 	imes 10^{-7}}{2 	imes 2\pi 	imes 10^{-2}} \sqrt{3^2 + 4^2}$.$B_{net} = \frac{4\pi 	imes 10^{-7}}{4\pi 	imes 10^{-2}} \sqrt{9 + 16} = 10^{-5} 	imes \sqrt{25} = 5 	imes 10^{-5} \, Wb/m^2$.

Two concentric coils each of radius equal to $2\pi \, cm$ are placed at right angles to each other. $3 \, A$ and $4 \, A$ are the currents flowing in each coil respectively. The magnetic induction in $Wb/m^2$ at the centre of the coils will be $(\mu_0 = 4\pi \times 10^{-7} \, Wb/A \cdot m)$.

Similar Questions

In the figure,what is the magnetic field at the point $O$?

$A$ horizontal overhead power line carries a current of $90 \;A$ in east to west direction. What is the magnitude and direction of the magnetic field due to the current $1.5 \;m$ below the line?

In the following figure,the magnitude of the magnetic field at the point $P$ is:

$A$ circular current-carrying coil has radius $R$. The magnetic induction at the centre of the coil is $B_{C}$. The magnetic induction of the coil at a distance $\sqrt{3} R$ from the centre along the axis is $B_{A}$. The ratio $B_{A}: B_{C}$ is

Charge $q$ is uniformly spread on a thin ring of radius $R.$ The ring rotates about its axis with a uniform frequency $f \ Hz.$ The magnitude of magnetic induction at the center of the ring is

Vedclass Test Series

Exam Paper Generator

Online Exam Module