Two capacitors,one of capacity $C$ and other of capacity $C/2$ are connected to a $V$ volt battery,as shown in the figure. The work done in charging fully both the capacitors is
- A$\frac{1}{4} C V^2$
- B$\frac{3}{4} C V^2$
- C$\frac{1}{2} C V^2$
- D$3 C V^2$
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