Two cones with the same base radius 8, cm and | vedclass

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(B) When two cones with the same base radius and height are joined together along their bases,the base area is hidden,and the total surface area of th

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$855$

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(B) When two cones with the same base radius and height are joined together along their bases,the base area is hidden,and the total surface area of the resulting shape is the sum of the curved surface areas of the two cones.Given:Radius of the cone,$r = 8\, cm$Height of the cone,$h = 15\, cm$The slant height $l$ of each cone is given by $l = \sqrt{r^2 + h^2} = \sqrt{8^2 + 15^2} = \sqrt{64 + 225} = \sqrt{289} = 17\, cm$.The total surface area of the resulting shape is the sum of the curved surface areas of the two identical cones:Surface Area $= 2 	imes (\pi r l)$$= 2 	imes \pi 	imes 8 	imes 17$$= 272\pi\, cm^2$Using $\pi \approx \frac{22}{7}$:$= 272 	imes \frac{22}{7} = \frac{5984}{7} \approx 854.85\, cm^2$.Rounding to the nearest whole number,we get $855\, cm^2$.

Two cones with the same base radius $8\, cm$ and height $15\, cm$ are joined together along their bases. Find the surface area of the shape so formed. (in $cm^2$)

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