Two cubes,each of 10 , cm edge,are joined end | vedclass

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(B) When two cubes of edge $10 \, cm$ are joined end-to-end,they form a cuboid.Length of the resulting cuboid $(l) = 10 \, cm + 10 \, cm = 20 \, cm$.B

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$1000$

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(B) When two cubes of edge $10 \, cm$ are joined end-to-end,they form a cuboid.Length of the resulting cuboid $(l) = 10 \, cm + 10 \, cm = 20 \, cm$.Breadth of the resulting cuboid $(b) = 10 \, cm$.Height of the resulting cuboid $(h) = 10 \, cm$.The surface area of a cuboid is given by the formula: $2(lb + bh + hl)$.Substituting the values: $2(20 	imes 10 + 10 	imes 10 + 10 	imes 20) \, cm^2$.$= 2(200 + 100 + 200) \, cm^2$.$= 2(500) \, cm^2 = 1000 \, cm^2$.

Two cubes,each of $10 \, cm$ edge,are joined end-to-end. Then,the surface area of the resulting cuboid is ...... $cm^2$.

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