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(B) When two dice are thrown,the total number of possible outcomes is $6^2 = 36$.The sum of the numbers on the two dice can range from $2$ to $12$.The

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$\frac{1}{2}$

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(B) When two dice are thrown,the total number of possible outcomes is $6^2 = 36$.The sum of the numbers on the two dice can range from $2$ to $12$.The sum is an even number if it is $2, 4, 6, 8, 10,$ or $12$.Let us list the favorable outcomes for each even sum:- Sum $= 2: (1, 1) ightarrow 1$ outcome- Sum $= 4: (1, 3), (2, 2), (3, 1) ightarrow 3$ outcomes- Sum $= 6: (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) ightarrow 5$ outcomes- Sum $= 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) ightarrow 5$ outcomes- Sum $= 10: (4, 6), (5, 5), (6, 4) ightarrow 3$ outcomes- Sum $= 12: (6, 6) ightarrow 1$ outcomeTotal number of favorable outcomes $= 1 + 3 + 5 + 5 + 3 + 1 = 18$.Probability $= \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{18}{36} = \frac{1}{2}$.

Two dice are thrown. Find the probability that the sum is an even number.

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