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(C) When two dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $E$ be the event of getting a sum less than $11$.It is eas

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$\frac{11}{12}$

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(C) When two dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $E$ be the event of getting a sum less than $11$.It is easier to find the complement event $E'$,which is getting a sum of $11$ or more.The outcomes for a sum $\ge 11$ are: $(5, 6), (6, 5), (6, 6)$.There are $3$ such outcomes.Therefore,the number of favourable outcomes for $E$ is $36 - 3 = 33$.The probability $P(E) = \frac{33}{36} = \frac{11}{12}$.

Two dice are thrown simultaneously. What is the probability of obtaining a sum of the numbers less than $11$?

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