Two dice are thrown. If the first die shows 5 | vedclass

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(D) When two dice are thrown,the total number of outcomes where the first die shows $5$ is $6$. These outcomes are $(5, 1), (5, 2), (5, 3), (5, 4), (5

Vedclass · Accepted Answer

$\frac{2}{3}$

Vedclass · Answer

(D) When two dice are thrown,the total number of outcomes where the first die shows $5$ is $6$. These outcomes are $(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)$.We are looking for the outcomes where the sum of the numbers is $8$ or more.The sums for the given outcomes are:$(5, 1) ightarrow 6$$(5, 2) ightarrow 7$$(5, 3) ightarrow 8$$(5, 4) ightarrow 9$$(5, 5) ightarrow 10$$(5, 6) ightarrow 11$The favorable outcomes are $(5, 3), (5, 4), (5, 5), (5, 6)$,which are $4$ in total.The required probability is $\frac{	ext{Number of favorable outcomes}}{	ext{Total outcomes}} = \frac{4}{6} = \frac{2}{3}$.

Two dice are thrown. If the first die shows $5$,what is the probability that the sum of the numbers on both dice is $8$ or more than $8$?

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