Two differentiable functions $f(x)$ and $g(x)$ are such that $f''(x) > 0$ and $g''(x) < 0$ for all $x \in (a,b)$ and $\int_{a}^{b} f(x) dx = \int_{a}^{b} g(x) dx$. If $f(x) = g(x)$ for $x = \alpha, \beta \in (a,b)$ $(\alpha < \beta)$,then:

  • A
    $\int_{\alpha}^{\beta} (g(x) - f(x)) dx = \int_{a}^{\alpha} (f(x) - g(x)) dx + \int_{\beta}^{b} (f(x) - g(x)) dx$
  • B
    $\int_{\alpha}^{\beta} (g(x) - f(x)) dx = \int_{a}^{\alpha} (f(x) - g(x)) dx$
  • C
    $\int_{\alpha}^{\beta} (g(x) - f(x)) dx = \int_{\beta}^{b} (f(x) - g(x)) dx$
  • D
    $\int_{\alpha}^{\beta} (g(x) - f(x)) dx = \int_{\alpha}^{\beta} (f(x) - g(x)) dx$

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The function $f(x) = x^{3} - 6x^{2} + ax + b$ is such that $f(2) = f(4) = 0$. Consider two statements.
$(S_1)$ There exists $x_{1}, x_{2} \in (2, 4)$,$x_{1} < x_{2}$,such that $f^{\prime}(x_{1}) = -1$ and $f^{\prime}(x_{2}) = 0$.
$(S_2)$ There exists $x_{3}, x_{4} \in (2, 4)$,$x_{3} < x_{4}$,such that $f$ is decreasing in $(2, x_{4})$,increasing in $(x_{4}, 4)$ and $2f^{\prime}(x_{3}) = \sqrt{3}f(x_{4})$.
Then

$f(x)=4 \log _{e}(x-1)-2 x^{2}+4 x+5, x>1$,which one of the following is $NOT$ correct?

Match the functions of List $I$ with the items of List $II$.
List $I$List $II$
$A. 3x^4 - 2x^3 - 6x^2 + 6x + 1$$(I)$ has minimum value at $x = 4$
$B. x + \frac{1}{x}, \forall x < 0$$(II)$ has maximum value at $x = -1$
$C. x^4(7 - x)^3$$(III)$ has maximum value at $x = 4$
$D. x^4 + (8 - x)^4$$(IV)$ is decreasing in $[2, \infty)$
$(V)$ is increasing in $[2, \infty)$

Let $f(x) = x \cos^{-1}(-\sin |x|)$,$x \in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$. Then which of the following is true?

Let $f: R \rightarrow R$ be defined by $f(x) = \frac{x^2-3x-6}{x^2+2x+4}$. Then which of the following statements is (are) $TRUE$?
$(A)$ $f$ is decreasing in the interval $(-2, -1)$
$(B)$ $f$ is increasing in the interval $(1, 2)$
$(C)$ $f$ is onto
$(D)$ Range of $f$ is $[-\frac{3}{2}, 2]$

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