Two electric bulbs rated P_1 text{ watt}, V t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The power rating of a bulb is given by $P = \frac{V^2}{R}$,where $V$ is the rated voltage and $R$ is the resistance of the bulb.For the two bulbs,

Vedclass · Accepted Answer

$P_1 + P_2 	ext{ watt}$

Vedclass · Answer

(A) The power rating of a bulb is given by $P = \frac{V^2}{R}$,where $V$ is the rated voltage and $R$ is the resistance of the bulb.For the two bulbs,the resistances are $R_1 = \frac{V^2}{P_1}$ and $R_2 = \frac{V^2}{P_2}$.When connected in parallel to a voltage source $V$,the total power $P_p$ consumed is the sum of the power consumed by each bulb.Since the voltage across each bulb remains $V$,the power consumed by each bulb is its rated power.Therefore,the total power $P_p = P_1 + P_2$.

Two electric bulbs rated $P_1 \text{ watt}, V \text{ volts}$ and $P_2 \text{ watt}, V \text{ volts}$ are connected in parallel and $V \text{ volts}$ are applied to the combination. The total power consumed will be:

Similar Questions

If current in an electric bulb changes by $1\%$,then the power will change by ............ $\%$

How much heat (in $cal$) is produced when a $210 \, W$ bulb is kept on for $5 \, min$? (Given $J = 4.2 \, J/cal$)

$A$ household supply is $220 \, V$ with a fuse of $9 \, A$. What is the maximum number of $60 \, W$ bulbs that can be connected in parallel and operated simultaneously?

An electric bulb marked as $50 W - 200 V$ is connected across a $100 V$ supply. The present power of the bulb is (in $W$)

$5.0 \, A$ current is set up in an external circuit by a $6.0 \, V$ storage battery for $6.0 \, \text{minutes}$. The chemical energy of the battery is reduced by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module