Two electric resistors have equal values of resistance $R$. Each can be operated with a power of $320 \ W$ at $220 \ V$. If the two resistors are connected in series to a $110 \ V$ electric supply,then the power generated in each resistor is (in $W$)

The e.m.f. of a cell is $E \text{ volts}$ and its internal resistance is $r \text{ ohm}$. The resistance in the external circuit is also $r \text{ ohm}$. The potential difference across the cell will be

Two electric bulbs,rated at $(25\, W, 220\, V)$ and $(100\, W, 220\, V)$,are connected in series across a $220\, V$ voltage source. If the $25\, W$ and $100\, W$ bulbs draw powers $P_1$ and $P_2$ respectively,then

The resistance of an iron wire is $10\,\Omega$ and the temperature coefficient of resistivity is $5 \times 10^{-3}\,^{\circ}C^{-1}$. At $20\,^{\circ}C$,it carries $30\,mA$ of current. Keeping the potential difference between its ends constant,the temperature of the wire is raised to $120\,^{\circ}C$. The current in milliamperes that flows in the wire is:

Refer to the circuit shown. What will be the total power dissipation in the circuit if $P$ is the power dissipated in $R_1$ (in $P$)? It is given that $R_2 = 4 R_1$ and $R_3 = 12 R_1$.

Ratio of thermal energy released in two resistors $R$ and $3R$ connected in parallel in an electric circuit is: