Two electrical bulbs marked $40\, W, 220\, V$ and $60\, W, 220\, V$ are connected in series across a $220\, V$ supply. The effective power is $P_1$. When they are connected in parallel across the same supply, the effective power is $P_2$. The ratio $(P_1/P_2)$ is:

  • A
    $0.5$
  • B
    $0.48$
  • C
    $0.24$
  • D
    $0.16$

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Match the List-$I$ with the List-$II$ from the combination shown. In the left side (List-$I$) there are four different conditions and in the right side (List-$II$), there are ratios of heat produced in each resistance for each condition:
List-$I$List-$II$
$(I)$ Two wires of same resistance are connected in series and same current is passed through them$(A)$ $1:2$
$(II)$ Two wires of resistance $R$ and $2R$ $\Omega$ are connected in series and same $P.D.$ is applied across them$(B)$ $4:1$
$(III)$ Two wires of same resistance are connected in parallel and same current is flowing through them$(C)$ $1:1$
$(IV)$ Two wires of resistances in the ratio $1:2$ are connected in parallel and same $P.D.$ is applied across them$(D)$ $2:1$

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