Two electrolytic cells containing molten solu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Faraday's second law of electrolysis,when the same quantity of electricity is passed through different electrolytes connected in seri

Vedclass · Accepted Answer

$58.5$

Vedclass · Answer

(B) According to Faraday's second law of electrolysis,when the same quantity of electricity is passed through different electrolytes connected in series,the masses of the substances deposited are proportional to their equivalent masses.$\frac{	ext{Mass of } Ni}{	ext{Mass of } Al} = \frac{	ext{Equivalent mass of } Ni}{	ext{Equivalent mass of } Al}$Equivalent mass of $Ni = \frac{	ext{Atomic mass of } Ni}{	ext{Valency factor}} = \frac{58.5}{2} = 29.25 \ g/eq$Equivalent mass of $Al = \frac{	ext{Atomic mass of } Al}{	ext{Valency factor}} = \frac{27}{3} = 9 \ g/eq$Let the mass of $Ni$ be $w$.$\frac{w}{18} = \frac{29.25}{9}$$w = 18 	imes \frac{29.25}{9} = 2 	imes 29.25 = 58.5 \ g$Therefore,the weight of nickel obtained is $58.5 \ g$.

Similar Questions

The required charge for one equivalent weight of silver deposited on cathode is

When a current of $0.6 \ A$ is passed through an aqueous solution of $CuSO_4$ for $7 \ minutes$,what is the total quantity of electricity passed in Faradays?

When $X$ amperes of current is passed through molten $AlCl_3$ for $96.5$ $s$,$0.09$ $g$ of aluminium is deposited. What is the value of $X$?

$0.50 \, L$ of a $0.60 \, M$ $CuSO_4$ solution is electrolyzed for a period of $30.0 \, min$ using a current of $4.60 \, A$. If inert electrodes are used,what is the final concentration of $Cu^{2+}$ remaining in the solution? $M$

During the electrolysis of an electrolyte,the number of ions produced is directly proportional to the

Vedclass Test Series

Exam Paper Generator

Online Exam Module