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(B) The Law of Multiple Proportions states that when two elements combine to form more than one compound,the masses of one element that combine with a

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$48$ parts by weight of $Y$

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(B) The Law of Multiple Proportions states that when two elements combine to form more than one compound,the masses of one element that combine with a fixed mass of the other are in the ratio of small whole numbers.Given that for a fixed mass of $X$,the masses of $Y$ in compounds $A, B, C, D, E$ are in the ratio $1 : 2 : 3 : 4 : 5$.In compound $A$,$28$ parts of $X$ combine with $16$ parts of $Y$.Since the ratio of $Y$ for a fixed amount of $X$ in compound $C$ is $3$ times that of compound $A$,the mass of $Y$ in compound $C$ is $16 	imes 3 = 48$ parts.Therefore,compound $C$ contains $28$ parts of $X$ and $48$ parts of $Y$.

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