Two equal forces (P each) act at a point incl | vedclass

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(C) The magnitude of the resultant $R$ of two vectors $A$ and $B$ inclined at an angle $	heta$ is given by the formula: $R = \sqrt{A^2 + B^2 + 2AB \c

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$P$

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(C) The magnitude of the resultant $R$ of two vectors $A$ and $B$ inclined at an angle $	heta$ is given by the formula: $R = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$ Given that the two forces are equal,$A = B = P$,and the angle between them is $	heta = 120^\circ$. Substituting these values into the formula: $R = \sqrt{P^2 + P^2 + 2(P)(P) \cos(120^\circ)}$ Since $\cos(120^\circ) = -1/2$: $R = \sqrt{2P^2 + 2P^2(-1/2)}$ $R = \sqrt{2P^2 - P^2}$ $R = \sqrt{P^2} = P$ Therefore,the magnitude of the resultant force is $P$.

Two equal forces ($P$ each) act at a point inclined to each other at an angle of $120^\circ$. The magnitude of their resultant is

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