Two equations are given below:A. oint E cdot | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Equation $A$ is $\oint E \cdot dA = \frac{Q}{\varepsilon_0}$, which is the Gauss law for electrostatics. It states that the total electric flux th

Vedclass · Accepted Answer

$A$. Gauss law for electric fields, $B$. Gauss law for magnetic fields

Vedclass · Answer

(B) Equation $A$ is $\oint E \cdot dA = \frac{Q}{\varepsilon_0}$, which is the Gauss law for electrostatics. It states that the total electric flux through a closed surface is equal to the enclosed charge divided by the permittivity of free space.Equation $B$ is $\oint B \cdot dA = 0$, which is the Gauss law for magnetism. It implies that magnetic monopoles do not exist, meaning the net magnetic flux through any closed surface is always zero.

Two equations are given below:
$A. \oint E \cdot dA = \frac{Q}{\varepsilon_0}$
$B. \oint B \cdot dA = 0$
They are:

Similar Questions

Gauss's law should be invalid if

The expression for an electric field is given by $\vec{E} = 4000 x^2 \hat{i} \text{ V/m}$. The electric flux through the cube of side $20 \text{ cm}$ when placed in the electric field (as shown in the figure) is $......... \text{ V cm}$.

$A$ point charge '$Q$' is placed at a point inside a hollow conducting sphere. Which of the following electric field patterns is correct?

The number of electric lines that emerge from a finite charge $+q$ is . . . . . . .

$A$ metallic solid sphere is placed in a uniform electric field. The lines of force follow the path$(s)$ shown in the figure as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Two equations are given below:$A. \oint E \cdot dA = \frac{Q}{\varepsilon_0}$$B. \oint B \cdot dA = 0$They are: