Two full turns of the circular scale of a scr | vedclass

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(A) The pitch of the screw gauge is the distance moved by the spindle in one full rotation. Since $2$ full turns cover $1\,mm$,the pitch is $	ext{pit

Vedclass · Accepted Answer

$3.32$

Vedclass · Answer

(A) The pitch of the screw gauge is the distance moved by the spindle in one full rotation. Since $2$ full turns cover $1\,mm$,the pitch is $	ext{pitch} = \frac{1\,mm}{2} = 0.5\,mm$.The least count $(LC)$ is given by $\frac{	ext{pitch}}{	ext{total divisions}} = \frac{0.5\,mm}{50} = 0.01\,mm$.The observed diameter is calculated as $	ext{Main Scale Reading} + (	ext{Circular Scale Division} 	imes LC)$.$	ext{Observed diameter} = 3\,mm + (35 	imes 0.01\,mm) = 3.35\,mm$.The actual diameter is given by $	ext{Actual diameter} = 	ext{Observed diameter} - 	ext{Zero error}$.$	ext{Actual diameter} = 3.35\,mm - (+0.03\,mm) = 3.32\,mm$.

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