Two identical bodies are made of a material f | vedclass

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(B) Let the heat capacity of the body at $100^{\circ} C$ be $C_1$ and the heat capacity of the body at $0^{\circ} C$ be $C_2$.Since the heat capacity

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more than $50^{\circ} C$

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(B) Let the heat capacity of the body at $100^{\circ} C$ be $C_1$ and the heat capacity of the body at $0^{\circ} C$ be $C_2$.Since the heat capacity increases with temperature,the body at $100^{\circ} C$ has a higher heat capacity than the body at $0^{\circ} C$,i.e.,$C_1 > C_2$.When the two bodies are brought into contact,heat flows from the hotter body to the colder body until they reach a common final temperature $T$.Assuming no heat loss to the environment,the heat lost by the hotter body equals the heat gained by the colder body:$C_1(100 - T) = C_2(T - 0)$$100 C_1 - C_1 T = C_2 T$$100 C_1 = T(C_1 + C_2)$$T = 100 \cdot \frac{C_1}{C_1 + C_2}$Since $C_1 > C_2$,the ratio $\frac{C_1}{C_1 + C_2} > \frac{1}{2}$.Therefore,$T > 100 \cdot \frac{1}{2} = 50^{\circ} C$.Thus,the final temperature is more than $50^{\circ} C$.

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