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(D) The force of repulsion between two charges is given by Coulomb's law: $F = \frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1} q_{2}}{r^{2}}$.Given: $F =

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$2 \mu	ext{C}$

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(D) The force of repulsion between two charges is given by Coulomb's law: $F = \frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1} q_{2}}{r^{2}}$.Given: $F = 10 	ext{ mg wt} = 10 	imes 10^{-3} 	ext{ kg} 	imes 10 	ext{ ms}^{-2} = 0.1 	ext{ N}$.Distance $r = 0.6 	ext{ m}$.Since the charges are identical,let $q_{1} = q_{2} = q$.Substituting the values: $0.1 = (9 	imes 10^{9}) 	imes \frac{q^{2}}{(0.6)^{2}}$.$q^{2} = \frac{0.1 	imes 0.36}{9 	imes 10^{9}} = \frac{0.036}{9 	imes 10^{9}} = 0.004 	imes 10^{-9} = 4 	imes 10^{-12} 	ext{ C}^{2}$.Taking the square root: $q = \sqrt{4 	imes 10^{-12}} = 2 	imes 10^{-6} 	ext{ C} = 2 \mu	ext{C}$.

Two identical charges repel each other with a force equal to $10 \text{ mg}$ wt when they are $0.6 \text{ m}$ apart in air $(g = 10 \text{ ms}^{-2})$. The value of each charge is:

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