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(A) When rod $P$ moves to the left,the area of the loop formed by the rails and the two rods increases. According to Faraday's law,an induced $EMF$ is

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will be attracted towards $P$

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(A) When rod $P$ moves to the left,the area of the loop formed by the rails and the two rods increases. According to Faraday's law,an induced $EMF$ is generated in the circuit,which drives an induced current. By Lenz's law,the direction of this induced current is such that it opposes the cause of its production,which is the increase in the magnetic flux through the loop. To oppose the increase in flux,the magnetic force on rod $Q$ must act in a direction that tends to decrease the area of the loop. Therefore,rod $Q$ will experience a force towards the left,i.e.,it will be attracted towards rod $P$.

Two identical conductors $P$ and $Q$ are placed on two frictionless rails $R$ and $S$ in a uniform magnetic field directed into the plane. If $P$ is moved in the direction shown in the figure with a constant speed,then rod $Q$

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