Two identical thin isosceles prisms of refracting angle $A$ and refractive index $\mu$ are placed with their bases touching each other. Two parallel rays of light are incident on this system at a distance $h$ from the principal axis as shown. The distance of the point where the rays converge from the prism is:

The refractive index of the material of a glass prism is $\sqrt{3}$. If the angle of minimum deviation is equal to the angle of the prism,then the angle of the prism is:
$\left(\cos 30^{\circ} = \frac{\sqrt{3}}{2} = \sin 60^{\circ}, \sin 30^{\circ} = \frac{1}{2} = \cos 60^{\circ}\right)$ (in $^{\circ}$)

In a thin prism of glass (refractive index $\mu = 1.5$),which of the following relations between the angle of minimum deviation $\delta_m$ and the angle of refraction $r$ is correct?

$A$ light ray is incident on an equilateral prism made of a material with a refractive index of $\sqrt{3}$. Inside the prism,if the light ray moves parallel to the base of the prism,then the angle of incidence of the light ray is: (in $^{\circ}$)

$A$ ray of light suffers minimum deviation when incident on a $60^{\circ}$ prism of refractive index $\sqrt{2}$. The angle of incidence is......$^{\circ}$

Assertion: There exist two angles of incidence for the same magnitude of deviation (except for minimum deviation) by a prism kept in air.
Reason: In a prism kept in air,a ray is incident on the first surface and emerges out of the second surface. If another ray is incident on the second surface along the path of the previous emergent ray,then this ray emerges out of the first surface along the path of the previous incident ray. This principle is called the principle of reversibility of light.