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(C) $NAND$ gate performs the operation $Y = \overline{A \cdot B}$.If the two inputs $A$ and $B$ are shorted, then $A = B = X$.Substituting this into t

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$NOT$ gate

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(C) $NAND$ gate performs the operation $Y = \overline{A \cdot B}$.If the two inputs $A$ and $B$ are shorted, then $A = B = X$.Substituting this into the $NAND$ expression, we get $Y = \overline{X \cdot X}$.Since $X \cdot X = X$, the expression becomes $Y = \overline{X}$.This is the Boolean expression for a $NOT$ gate.Therefore, a $NAND$ gate with shorted inputs acts as a $NOT$ gate.

Two inputs of a $NAND$ gate are shorted. This gate is equivalent to

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