Two isomers A and B with molecular formula C_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The molecular formula $C_4H_8$ corresponds to alkenes. Oxidation of alkenes with acidic $KMnO_4$ leads to cleavage of the double bond. $2-$methylp

Vedclass · Accepted Answer

$2-$methylpropene

Vedclass · Answer

(D) The molecular formula $C_4H_8$ corresponds to alkenes. Oxidation of alkenes with acidic $KMnO_4$ leads to cleavage of the double bond. $2-$methylpropene $(CH_3)_2C=CH_2$ on oxidation with acidic $KMnO_4$ gives acetone $(CH_3)_2C=O$ and $CO_2$ gas,which causes effervescence. The reaction is: $(CH_3)_2C=CH_2 + [O] \xrightarrow{KMnO_4/H^+} (CH_3)_2C=O + CO_2 + H_2O$. Thus,compound $A$ is $2-$methylpropene.

Two isomers $A$ and $B$ with molecular formula $C_4H_8$ give different products on oxidation with $KMnO_4$ in acidic medium. Isomer $A$ on reaction with $KMnO_4 / H^{+}$ results in effervescence of a gas and gives a ketone. The compound $A$ is ...... .

Similar Questions

Conc. $H_2SO_4$ reacts with $C_2H_5OH$ at $170\,^{\circ}C$ to form

Explain the hybridization of carbon and the bond structure of ethene $\left( C_2H_4 \right)$ $OR$ Explain: Ethene is a planar molecule.

Markovnikov's rule guides the addition of $HBr$ to which of the following compounds?

The product of the following reaction: $CH_2=CH-CCl_3 + HBr$ is:

The major products '$A$' and '$B$',respectively,are

Vedclass Test Series

Exam Paper Generator

Online Exam Module