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(A) Both the bulbs are connected in parallel. Therefore,the potential difference across each of them will be $220\, V$,because the voltage remains the

Vedclass · Accepted Answer

$0.73$

Vedclass · Answer

(A) Both the bulbs are connected in parallel. Therefore,the potential difference across each of them will be $220\, V$,because the voltage remains the same in a parallel circuit.For the first bulb $(100\, W, 220\, V)$:$I_1 = \frac{P_1}{V} = \frac{100}{220}\, A$For the second bulb $(60\, W, 220\, V)$:$I_2 = \frac{P_2}{V} = \frac{60}{220}\, A$Total current drawn from the line $(I)$ is the sum of currents through both bulbs:$I = I_1 + I_2 = \frac{100}{220} + \frac{60}{220} = \frac{160}{220}\, A$$I \approx 0.727\, A$Rounding to two decimal places,we get $0.73\, A$.

Two lamps,one rated $100\, W$ at $220\, V$,and the other $60\, W$ at $220\, V$,are connected in parallel to electric mains supply. What current (in $A$) is drawn from the line if the supply voltage is $220\, V$?

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