Two lithium nuclei in a lithium vapour at roo | vedclass

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(C) For two nuclei to fuse,they must overcome the electrostatic (Coulombic) repulsion between their positive charges.At room temperature,the kinetic e

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Nuclei do not come very close due to coulombic repulsion

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(C) For two nuclei to fuse,they must overcome the electrostatic (Coulombic) repulsion between their positive charges.At room temperature,the kinetic energy of the lithium nuclei is extremely low,which is insufficient to overcome the Coulomb barrier.As a result,the nuclei cannot get close enough to the range of the strong nuclear force (approximately $10^{-15} \ m$) to initiate fusion.Therefore,the correct reason is that the nuclei do not come very close due to Coulombic repulsion.

$I$	$II$
$(a). [Cr(H_2O)_6]^{2+}$	$[Cr(H_2O)_6]^{3+}$
$(b). [Fe(H_2O)_6]^{3+}$	$[Fe(CN)_6]^{3-}$
$(c). [Fe(CN)_6]^{3-}$	$[Ru(CN)_6]^{3-}$
$(d). [NiF_6]^{4-}$	$[NiF_6]^{2-}$

Two lithium nuclei in a lithium vapour at room temperature do not combine to form a carbon nucleus because

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