Two long straight parallel conductors 10 text | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic field $B$ at a distance $r$ from a long straight current-carrying conductor is given by $B = \frac{\mu_0 I}{2 \pi r}$.Let the two con

Vedclass · Accepted Answer

zero

Vedclass · Answer

(C) The magnetic field $B$ at a distance $r$ from a long straight current-carrying conductor is given by $B = \frac{\mu_0 I}{2 \pi r}$.Let the two conductors be placed at a distance $d = 10 	ext{ cm} = 0.1 	ext{ m}$.At the midpoint,the distance from each conductor is $r = \frac{d}{2} = 0.05 	ext{ m}$.For the first conductor,the magnetic field $B_1$ at the midpoint is directed into the plane (using the right-hand thumb rule).For the second conductor,the magnetic field $B_2$ at the midpoint is directed out of the plane.Since the currents are equal $(I_1 = I_2 = 3 	ext{ A})$ and the distances are equal,the magnitudes of the magnetic fields are equal: $B_1 = B_2 = \frac{\mu_0 I}{2 \pi r}$.Since the fields are equal in magnitude and opposite in direction,the net magnetic field $B_{net} = B_1 - B_2 = 0$.

Two long straight parallel conductors $10 \text{ cm}$ apart,carry equal currents of magnitude $3 \text{ A}$ in the same direction. Then,the magnetic induction at a point midway between them is

Similar Questions

The unit vectors $\hat{i}, \hat{j},$ and $\hat{k}$ are as shown below. What will be the magnetic field at $O$ in the following figure?

Find the magnetic field at $P$ due to the arrangement shown.

$A$ coil of $12$ turns is made from a wire of constant length carrying a current $I$. If the number of turns is changed to $3$,what is the percentage change in the magnetic field produced at its centre?

Which one of the following options represents the magnetic field $\vec{B}$ at the origin $O$ due to the current $I$ flowing in the given wire segments lying on the $xy$ plane?

Vedclass Test Series

Exam Paper Generator

Online Exam Module