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(B) The magnetic field $B$ due to a long straight wire carrying current $I$ at a distance $d$ is given by $B = \frac{\mu_0 I}{2 \pi d}$.At the midpoin

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(B) The magnetic field $B$ due to a long straight wire carrying current $I$ at a distance $d$ is given by $B = \frac{\mu_0 I}{2 \pi d}$.At the midpoint $P$ between the two wires,the distance from each wire is $d$.The magnetic field due to the first wire at $P$ is $B_1 = \frac{\mu_0 I}{2 \pi d}$ (directed into the page by the right-hand rule).The magnetic field due to the second wire at $P$ is $B_2 = \frac{\mu_0 I}{2 \pi d}$ (directed out of the page by the right-hand rule).Since the currents are in the same direction,the magnetic fields at the midpoint are equal in magnitude and opposite in direction.Therefore,the net magnetic field $B_{net} = B_1 - B_2 = 0$.

Two long straight parallel wires are separated by a distance $2d$. Each wire carries a current $I$ in the same direction. The magnetic field at a point $P$ midway between them is

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