Two masses,both equal to 100, g,are suspended | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{\ell}{g}}$.Given $\ell = 1.0\, m$ and taking $g = 10\, m/s^2$,we have $T = 2\pi

Vedclass · Accepted Answer

at $	heta = 0.0^o$,$0.50\, s$ later.

Vedclass · Answer

(A) The period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{\ell}{g}}$.Given $\ell = 1.0\, m$ and taking $g = 10\, m/s^2$,we have $T = 2\pi \sqrt{\frac{1}{10}} \approx 2\pi 	imes 0.316 \approx 1.987\, s \approx 2.0\, s$.Since the period $T$ is independent of the amplitude for small angles,both pendulums have the same period $T = 2.0\, s$.They are released from rest at $t = 0$. The time taken for a pendulum to reach the vertical position $(	heta = 0^o)$ from its extreme position is one-quarter of its time period,i.e.,$t = \frac{T}{4}$.Thus,$t = \frac{2.0}{4} = 0.5\, s$.Both pendulums reach the vertical position at the same time $t = 0.5\, s$,so they will collide at $	heta = 0.0^o$ after $0.50\, s$.

Similar Questions

The bob of a simple pendulum of length $200 \ cm$ is released from a horizontal position. If $10 \%$ of its initial energy is lost due to air resistance,then the speed of the bob at the mean position is (Acceleration due to gravity $= 10 \ m \ s^{-2}$) (in $m \ s^{-1}$)

$A$ simple pendulum has a time period $T$ in air. Its time period when it is completely immersed in a liquid of density one-eighth the density of the material of the bob is:

The amplitude of an oscillating simple pendulum is $10 \ cm$ and its period is $4 \ s$. Its speed $1 \ s$ after it passes its equilibrium position is ... $m/s$.

The time period of a simple pendulum inside a stationary lift is $\sqrt{3} \ s$. When the lift moves upwards with an acceleration $g/3$,the new time period will be ($g=$ acceleration due to gravity).

$A$ pendulum bob is swinging in a vertical plane such that its angular amplitude is less than $90^o$. At its highest point,the string is cut. Which trajectory is possible for the bob afterwards?

Vedclass Test Series

Exam Paper Generator

Online Exam Module