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(D) Given masses are $m_1 = 2 \, kg$ and $m_2 = 3 \, kg$.For a system of two masses connected by a string over a fixed pulley,the tension $T$ is given

Vedclass · Accepted Answer

$\frac{12g}{5}; \frac{g}{5}$

Vedclass · Answer

(D) Given masses are $m_1 = 2 \, kg$ and $m_2 = 3 \, kg$.For a system of two masses connected by a string over a fixed pulley,the tension $T$ is given by $T = \frac{2m_1m_2}{m_1 + m_2}g$.Substituting the values: $T = \frac{2 	imes 2 	imes 3}{2 + 3}g = \frac{12}{5}g$.The acceleration $a$ of the system is given by $a = \left( \frac{m_2 - m_1}{m_1 + m_2} ight)g$.Substituting the values: $a = \left( \frac{3 - 2}{3 + 2} ight)g = \frac{1}{5}g = \frac{g}{5}$.Thus,the tension is $\frac{12g}{5}$ and the acceleration is $\frac{g}{5}$.

Two masses $2 \, kg$ and $3 \, kg$ are attached to the ends of a string passed over a pulley fixed at the top. The tension and acceleration are:

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