(B) The initial capacitance of the parallel plate capacitor with air as the dielectric is given by $C = \frac{\varepsilon_0 A}{d}$.When a metal plate

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) The initial capacitance of the parallel plate capacitor with air as the dielectric is given by $C = \frac{\varepsilon_0 A}{d}$.When a metal plate of thickness $t = \frac{d}{2}$ is inserted between the plates,the effective distance between the plates becomes $d_{eff} = d - t = d - \frac{d}{2} = \frac{d}{2}$.The new capacitance $C^{\prime}$ is given by $C^{\prime} = \frac{\varepsilon_0 A}{d - t} = \frac{\varepsilon_0 A}{d/2} = \frac{2 \varepsilon_0 A}{d}$.Substituting the expression for $C$,we get $C^{\prime} = 2C$.Therefore,the ratio $\frac{C^{\prime}}{C} = 2$.

Class 12 Physics Electrostatic Potential and Capacitance Effect of Dielectric Inside Capacitor

Difficult

Two metal plates each of area $A$ form a parallel plate capacitor with air in between the plates. The distance between the plates is $d$. $A$ metal plate of thickness $\frac{d}{2}$ and of same area $A$ is inserted between the plates to form two capacitors of capacitances $C_1$ and $C_2$ as shown in the figure. If the effective capacitance of the two capacitors is $C^{\prime}$ and the capacitance of the capacitor initially is $C$,then $\frac{C^{\prime}}{C}$ is

TS EAMCET 2013 All TS EAMCET

AP EAMCET 2013 All AP EAMCET

A
$4$
B
$2$
C
$6$
D
$1$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Electrostatic Potential and Capacitance

Subtopic

Effect of Dielectric Inside Capacitor

Previous Year

TS EAMCET 2013 Paper All TS EAMCET years →

Previous Year

AP EAMCET 2013 Paper All AP EAMCET years →

When a slab of dielectric material is introduced between the parallel plates of a capacitor which remains connected to a battery,then the charge on the plates relative to the earlier charge:

Easy

View Solution

In a parallel plate air capacitor of plate separation $d$,a dielectric slab of thickness $t$ is introduced between the plates $(t < d)$. The capacitance becomes one-third of the original value. The dielectric constant of the slab will be

DifficultMHT CET 2022

View Solution

In the given figure,there are two capacitors in series. $A$ rigid conducting slab of thickness $b$ can slide vertically. Find the equivalent capacitance of the system.

Difficult

View Solution

Two parallel plates have equal and opposite charges. When the space between them is evacuated,the electric field between the plates is $2 \times 10^5 \ V/m$. When the space is filled with a dielectric,the electric field becomes $1 \times 10^5 \ V/m$. Find the dielectric constant of the dielectric material.

Medium

View Solution

$A$ parallel plate capacitor has a plate area of $40\,cm^2$ and a plate separation of $2\,mm$. The space between the plates is filled with a dielectric medium of thickness $1\,mm$ and dielectric constant $5$. The capacitance of the system is:

MediumJEE MAIN 2023

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

When a slab of dielectric material is introduced between the parallel plates of a capacitor which remains connected to a battery,then the charge on the plates relative to the earlier charge:

In a parallel plate air capacitor of plate separation $d$,a dielectric slab of thickness $t$ is introduced between the plates $(t < d)$. The capacitance becomes one-third of the original value. The dielectric constant of the slab will be

In the given figure,there are two capacitors in series. $A$ rigid conducting slab of thickness $b$ can slide vertically. Find the equivalent capacitance of the system.

$A$ parallel plate capacitor has a plate area of $40\,cm^2$ and a plate separation of $2\,mm$. The space between the plates is filled with a dielectric medium of thickness $1\,mm$ and dielectric constant $5$. The capacitance of the system is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module