Two moles of benzaldehyde and one mole of ace | vedclass

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(A) The reaction between two moles of benzaldehyde $(C_6H_5CHO)$ and one mole of acetone $(CH_3COCH_3)$ in the presence of aqueous $NaOH$ and heat is

Vedclass · Accepted Answer

$9$

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(A) The reaction between two moles of benzaldehyde $(C_6H_5CHO)$ and one mole of acetone $(CH_3COCH_3)$ in the presence of aqueous $NaOH$ and heat is a Claisen-Schmidt condensation reaction.The product $x$ formed is dibenzylideneacetone,which has the structure: $C_6H_5-CH=CH-CO-CH=CH-C_6H_5$.To calculate the number of $\pi$ bonds in dibenzylideneacetone:$1$. Each phenyl ring $(C_6H_5)$ contains $3$ $\pi$ bonds.$2$. There are two phenyl rings,so $2 	imes 3 = 6$ $\pi$ bonds.$3$. There are two $C=C$ double bonds,contributing $2$ $\pi$ bonds.$4$. There is one $C=O$ double bond,contributing $1$ $\pi$ bond.Total $\pi$ bonds = $6 + 2 + 1 = 9$.

Two moles of benzaldehyde and one mole of acetone under alkaline conditions using aqueous $NaOH$ after heating gives $x$ as the major product. The number of $\pi$ bonds in the product $x$ is.................

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