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(D) Let the third number be $100$.Since the first number is $30 \%$ more than the third number,the first number $= 100 + 30 = 130$.Since the second nu

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$92 \frac{6}{7}$

Vedclass · Answer

(D) Let the third number be $100$.Since the first number is $30 \%$ more than the third number,the first number $= 100 + 30 = 130$.Since the second number is $40 \%$ more than the third number,the second number $= 100 + 40 = 140$.According to the question,the first number is $x \%$ of the second number.Therefore,$130 = \frac{x}{100} 	imes 140$.Solving for $x$: $x = \frac{130 	imes 100}{140} = \frac{13000}{140} = \frac{650}{7}$.Converting to a mixed fraction: $x = 92 \frac{6}{7}$.

Two numbers are $30 \%$ and $40 \%$ more than the third number respectively. The first number is $x \%$ of the second. Then $x = ?$

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