Two numbers are less than a third number by 3 | vedclass

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(B) Let the third number be $100$.Since the first number is $30 \%$ less than the third number,the first number $= 100 - 30 = 70$.Since the second num

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$10$

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(B) Let the third number be $100$.Since the first number is $30 \%$ less than the third number,the first number $= 100 - 30 = 70$.Since the second number is $37 \%$ less than the third number,the second number $= 100 - 37 = 63$.We need to find how much per cent the second number is less than the first number.Difference between the first and second number $= 70 - 63 = 7$.Percentage less $= \left( \frac{	ext{Difference}}{	ext{First number}} 	imes 100 ight) \% = \left( \frac{7}{70} 	imes 100 ight) \% = 10 \%$.

Two numbers are less than a third number by $30 \%$ and $37 \%$,respectively. How much per cent is the second number less than the first?

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