Two objects are projected with the same velocity '$u$' but at different angles $\alpha$ and $\beta$ with the horizontal. If $\alpha + \beta = 90^{\circ}$,the ratio of the horizontal range of the first object to the $2^{\text{nd}}$ object will be:

  • A
    $4:1$
  • B
    $2:1$
  • C
    $1:2$
  • D
    $1:1$

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