Two oxides of nitrogen,NO and NO_2 are allowe | vedclass

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(A) The reaction between $NO$ and $NO_2$ at $243 \ K$ produces dinitrogen trioxide,$N_2O_3$ (blue coloured solid),which is compound $(X)$.$NO(g) + NO_

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triangular planar

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(A) The reaction between $NO$ and $NO_2$ at $243 \ K$ produces dinitrogen trioxide,$N_2O_3$ (blue coloured solid),which is compound $(X)$.$NO(g) + NO_2(g) \xrightarrow{243 \ K} N_2O_3(s) (X)$When $N_2O_3$ reacts with water,it forms nitrous acid,$HNO_2$,which is compound $(Y)$.$N_2O_3 + H_2O \rightarrow 2HNO_2 (Y)$The anion of $HNO_2$ is the nitrite ion,$NO_2^-$.In $NO_2^-$,the nitrogen atom is $sp^2$ hybridized with one lone pair of electrons.Due to the presence of one lone pair,the shape of the $NO_2^-$ ion is bent or angular,but based on the options provided and the geometry of the $sp^2$ hybridization,it is often described in the context of its planar arrangement as triangular planar (with one vertex occupied by a lone pair).Therefore,the correct option is $A$.

Two oxides of nitrogen,$NO$ and $NO_2$ are allowed to react together at $243 \ K$ to form a coloured compound of nitrogen $(X)$. When compound $(X)$ reacts with water,it yields another compound of nitrogen $(Y)$. The shape of the anion of $(Y)$ molecule is:

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