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Question

(D) Given:Horizontal distance $x = 100 \,m$Vertical displacement $y = 10 \,cm = 0.1 \,m$Initial vertical velocity $u_y = 0$Acceleration due to gravity

Vedclass · Accepted Answer

$700$

Vedclass · Answer

(D) Given:Horizontal distance $x = 100 \,m$Vertical displacement $y = 10 \,cm = 0.1 \,m$Initial vertical velocity $u_y = 0$Acceleration due to gravity $g = 10 \,m/s^2$For horizontal projectile motion,the vertical displacement $y$ is given by:$y = \frac{1}{2} g t^2$$0.1 = \frac{1}{2} 	imes 10 	imes t^2$$0.1 = 5 t^2$$t^2 = 0.02$$t = \sqrt{0.02} \,s$The horizontal distance $x$ is covered with constant horizontal velocity $u$:$x = u 	imes t$$100 = u 	imes \sqrt{0.02}$$u = \frac{100}{\sqrt{0.02}} = \frac{100}{\sqrt{2 	imes 10^{-2}}} = \frac{100}{0.1414} \approx 707 \,m/s$Thus,the velocity of the bullet at $A$ is nearly $700 \,m/s$.

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