Two parallel rail tracks run north-south. Tra | vedclass

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Question

(B) Let the positive direction of the $x$-axis be from south to north.The velocity of train $A$ is $v_{A} = +54\; km\; h^{-1} = 54 	imes \frac{5}{18}

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(B) Let the positive direction of the $x$-axis be from south to north.The velocity of train $A$ is $v_{A} = +54\; km\; h^{-1} = 54 	imes \frac{5}{18}\; m\; s^{-1} = +15\; m\; s^{-1}$.The velocity of the monkey with respect to train $A$ is $v_{MA} = -18\; km\; h^{-1}$ (since it moves against the motion of the train).Converting this to $m\; s^{-1}$: $v_{MA} = -18 	imes \frac{5}{18}\; m\; s^{-1} = -5\; m\; s^{-1}$.We know that the relative velocity of the monkey with respect to train $A$ is given by $v_{MA} = v_{M} - v_{A}$,where $v_{M}$ is the velocity of the monkey with respect to the ground.Substituting the values: $-5\; m\; s^{-1} = v_{M} - 15\; m\; s^{-1}$.Therefore,$v_{M} = 15\; m\; s^{-1} - 5\; m\; s^{-1} = 10\; m\; s^{-1}$.

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