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(B) Let the capacity of the tank be $C$ gallons.The first pipe fills the tank in $24$ minutes,so its rate is $\frac{C}{24}$ gallons/minute.The second

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$600$

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(B) Let the capacity of the tank be $C$ gallons.The first pipe fills the tank in $24$ minutes,so its rate is $\frac{C}{24}$ gallons/minute.The second pipe fills the tank in $40$ minutes,so its rate is $\frac{C}{40}$ gallons/minute.The third pipe empties the tank at a rate of $30$ gallons/minute.When all three pipes are open,the net rate of filling is $\frac{C}{24} + \frac{C}{40} - 30$ gallons/minute.Since the tank is filled in $1$ hour ($60$ minutes),we have:$60 	imes (\frac{C}{24} + \frac{C}{40} - 30) = C$Simplify the expression inside the parentheses:$\frac{5C + 3C}{120} - 30 = \frac{C}{60}$$\frac{8C}{120} - 30 = \frac{C}{60}$$\frac{C}{15} - 30 = \frac{C}{60}$Multiply the entire equation by $60$ to clear the denominators:$4C - 1800 = C$$3C = 1800$$C = 600$Therefore,the capacity of the tank is $600$ gallons.

Two pipes can fill an empty tank separately in $24$ $minutes$ and $40$ $minutes$ respectively,and a third pipe can empty $30$ $gallons$ of water per $minute$. If all three pipes are opened,the empty tank becomes full in one $hour$. The capacity of the tank (in $gallons$) is:

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