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(C) Let the intensity of the incident unpolarized light be $I_0$.When unpolarized light passes through the first polarizer,the intensity of the transm

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$12.5$

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(C) Let the intensity of the incident unpolarized light be $I_0$.When unpolarized light passes through the first polarizer,the intensity of the transmitted polarized light becomes $I_1 = \frac{I_0}{2}$.According to Malus' Law,when this polarized light passes through the second polarizer whose principal plane is at an angle $	heta = 60^{\circ}$ to the first,the transmitted intensity $I_2$ is given by $I_2 = I_1 \cos^2 	heta$.Substituting the values: $I_2 = \left(\frac{I_0}{2}ight) \cos^2 60^{\circ} = \left(\frac{I_0}{2}ight) \left(\frac{1}{2}ight)^2 = \frac{I_0}{2} 	imes \frac{1}{4} = \frac{I_0}{8}$.The percentage of incident light that passes through the system is $\frac{I_2}{I_0} 	imes 100 = \frac{I_0/8}{I_0} 	imes 100 = \frac{100}{8} = 12.5 \%$.

Two polarizers are oriented with their principal planes making an angle of $60^{\circ}$ with each other. The percentage of incident unpolarized light which passes through the system is: (in $\%$)

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